DMX is 512 channels, 256 is exactly .5 of 512. So I would personally think that if it expects 14 Bit MIDI that we should divide by 0.5 * 16384 = 8192

 Hi Jurian, thanks for jumping in. But divide where? I am not sure what you mean. The size of the incoming number could be relatively arbitrary as the servos will just stop moving outside their scope. I changed my script from 256 to 127 and I get pretty consistent movement from 0 to 16384.

Now if it really makes the movement so much more high res is another question. I have come to believe that it really only matters if you need to make very precisely positioned stops.

Cheers

If the code of DMX is the following (and you know this is correct)

// iz_output 1 "LSB"

// iz_output 2 "MSB"

function main()

{

var input = arguments[0];   // input 1 [0-65535]

    var n = Math.trunc(input); // float to integer, maybe redundant

var LSB = n % 256; // for dmx this is how LSB is calculated

var MSB = Math.floor(n/256);  // for dmx this is how MSB is calculated

return [LSB, MSB]

}

DMX is 512 channels, 256 is exactly .5 of 512. So I would personally think that if it expects 14 Bit MIDI that we should divide by 0.5 * 16384 = 8192

Actually, it's supposed to be 14 bit (16384?) for midi, so now I am really curious if I am on the right track

Since each controller message has only a 7-bit value field, many MIDI devices utilize some controllers in pairs to achieve a full 14-bit resolution. These can be thought of as the “coarse” adjustment for the most significant 7-bits (MSB), and the “fine” adjustment for the least significant 7-bits (LSB).