[SOLVED] On the fly LOOP
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@dbini thanks for that!
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@michel thanks for your reply. I will try to use this solution asap.
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@dbini I tested your patch but in my computer it does not seem to work properly. The first time I click on the second trigger it starts a loop as expected. Then I click on the third trigger and it shifts back to normal mode as expected. But then, if I click on the second trigger again, it does not make a loop anymore. I am in the end of the semester in my University, grading a lot of students so I will not have time to do it today, but in a couple of days I will check the patch carefully and try to figure out what is happening.
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@dbini trying to understand your patch... i recreated it in another scene to make sense of what you've done. not sure if i got it all, neither if trying to organize it with user actos did any good. anyways follow attached. loop-on-the-fly.izz
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@michel @dbini follow attached a patch that allow on the fly loop using the Broadcaster and Listener actors. repeat2.izz
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i didn't make the patch to reset itself - i designed it for just one loop per movie. you can easily make it reset by adding some extra Trigger Value actors.
John Collingswood
taikabox.com
2019 MBPT 2.6GHZ i7 OSX15.3.2 16GB
plus an old iMac and assorted Mac Minis for installations -
actually - its not that easy, using this way of solving the problem you would have to build a new Envelope Generator system for each time you want to create a loop.
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I'm not 100% sure I got what you want to achieve but I tried to do what I understood... I only saw @dbini solution after solving it. But I give it here anyways, as it might be a bit less complex for some situations.
Best
Dill
Edit: Added a comment for better understanding and an extra function to have the clip stoping at end if loop mode is off. Changed screenshot to reflect the changes needed. -
nice one Dill - that's a simple way to solve the problem.
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@dillthekraut I wanted to have the movie loop at the position it is playing at a particular moment. the patch repeat2.izz I posted above archieves that, I guess now there are two solutions for the same problem.
